Respuesta :

dalendrk
[tex]g(x)=ax-2x\ln(x)\\\\x-intercept\ if\ g(x)=0\\\\subtitute\\\\ax-2x\ln(x)=0\\\\x=x(a-2\ln(x))=0\iff x=0\ or\ a-2\ln(x)=0\\\\Answer:\boxed{x=0}[/tex]
x-intercept => g(x) = 0
ax-2xln(x) = 0
x(a-2ln(x))=0

1. x=0 "F" because x>0

2. a-2ln(x)=0
ln(x)=a/2
[tex]x= e^{ \frac{a}{2} } [/tex]

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