Respuesta :

Chlidonias

Answer:

Option E

Step-by-step explanation:

if [tex]n\neq[/tex] 0, let us plugging different value for n

if n=1

2n = 2 x 1 = 2>n

but if n=-1

2n= 2 x -1 = -2<n

So I is not always true

Now, for the same value of n, let us check the other two statements

[tex]n^{2}[/tex] = [tex]1^{2}[/tex] = 1  which is not greater than n

So II is also not true

2 - n = 2 - 1 = 1 which is not greater than n

So we can see that none of the statement is true,

So the correct answer is option E

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