makiah37 makiah37

31-03-2020
Physics

contestada

What is the mass of a bullet moving at 970m/s if the bullet’s KE is 3.9x 10^3J

Respuesta :

Larrysammz Larrysammz

31-03-2020

Answer:

0.08kg

Explanation:

K.E = 1/2 mv^2

v = 970m/s

K.E = 3.9x 10^3J= 3900J

K.E = 1/2 mv^2

3900 = 1/2 m x 970x 970

3900 = 1/2 ×940900m

3900 = 470450m

m = 3900/470450 = 0.00828993516 = 0.008kg

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pohaj49061 pohaj49061

31-03-2020

I think the Answer is 0.08kg

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