Respuesta :

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Spring force is given be kx.

Where k is spring constant and x is the distance moved.

Using this relation,

[tex]5N = k(2 \times {10}^{ - 2}m ) \\ \\ k = 250N {m}^{ - 1} [/tex]

Cr1spyla1

Answer:

Use Hooke's law

Explanation:

  1. Apply formula: F = kx
  2. Sub values in: 5 = 0.02k
  3. Use algebra: k = 250
  4. The spring constant is 250 N/m

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