Answer:
v= 3.7 m/s (approx)
Explanation:
given
output power = 111 W
mass of bucket and water = 3 kg
speed v = ?
we know
[tex]power = force . velocity[/tex]
[tex]P = f.v[/tex] ................(i)
weight of bucket = 3×10 = 30
we use [tex]g = 10 m/s^2[/tex]
weight of bucket is force = 30 N
so velocity will be from (i) equation
[tex]v =\frac{P}{f}\\[/tex]
[tex]v =\frac{111}{30}[/tex]
v= 3.7 m/s (approx)