Respuesta :
Answer: The heat of combustion of the organic material is -69.88 kJ/g
Explanation:
To calculate the heat absorbed by the calorimeter, we use the equation:
[tex]q=c\Delta T[/tex]
where,
q = heat absorbed
c = heat capacity of calorimeter = 44.51 kJ/°C
[tex]\Delta T[/tex] = change in temperature = [tex]T_2-T_1=(29.28-23.13)^oC=6.15^oC[/tex]
Putting values in above equation, we get:
[tex]q=44.51kJ/^oC\times 6.15^oC=273.74kJ[/tex]
Heat absorbed by the calorimeter will be equal to the heat released by the reaction.
Sign convention of heat:
When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.
To calculate the enthalpy change of the reaction, we use the equation:
[tex]\Delta H_{rxn}=\frac{q}{m}[/tex]
where,
q = amount of heat released = -273.74 kJ
m = mass of organic material = 3.917 g
[tex]\Delta H_{rxn}[/tex] = enthalpy change of the reaction
Putting values in above equation, we get:
[tex]\Delta H_{rxn}=\frac{-273.74kJ}{3.917g}=-69.88kJ/g[/tex]
Hence, the heat of combustion of the organic material is -69.88 kJ/g
