Answer:
[tex]2 {x}^{2} + 5x - 58 = 0[/tex]
Step-by-step explanation:
The base of an open rectangular box is of length (2x + 5) cm and width x cm.
The area of a rectangle is
[tex] = length \times width[/tex]
We substitute the dimensions in terms of x.
The area of the base is
[tex] = x(2x + 5)[/tex]
This is equal to 58 as stated in the question.
This implies that:
[tex]x(2x + 5) = 58[/tex]
Expand to get:
[tex]2 {x}^{2} + 5x = 58[/tex]
Rewrite in standard form:
[tex]2 {x}^{2} + 5x - 58 = 0[/tex]
