Answer:
The magnitude of angular acceleration of the wheel = 0.26 [tex]\frac{rad}{s^{2} }[/tex]
Explanation:
Mass m = 10 kg
Diameter = 0.4 m
Initial speed [tex]\omega_{1} = 26 \ \frac{rad}{sec}[/tex]
Final speed [tex]\omega_{2} = 16 \ \frac{rad}{sec}[/tex]
Angle [tex]\theta[/tex] = 19 rad
The value of final speed is given by
[tex]\omega _{2} = \omega _{1} + 2 \alpha \theta[/tex]
Put all the values in above equation we get
16 = 26 + 2 ([tex]\alpha[/tex]) (19)
[tex]\alpha[/tex] = - 0.26 [tex]\frac{rad}{s^{2} }[/tex]
Therefore the magnitude of angular acceleration of the wheel = 0.26 [tex]\frac{rad}{s^{2} }[/tex]
