383.5 grams is the mass of water should be added to 22.0 g of KCl to make a 5.50 % by mass solution.
Explanation:
Given that:
Solution to be prepared is 5.5 %
mass of KCl is 22 gram
mass of water required =?
5.5 % solution means that
5.5 grams in 100 ml or gram of water to make solution.
let the water required is 5.5 + x, so the equation will be
5.5 =[tex]\frac{22}{22+x}[/tex] x 100
121+ 5.5x = 2200
5.5 x = 2200-121
x = [tex]\frac{2079}{5.5}[/tex]
x = 378 grams
The mass of water added to KCl to make it 5.5% percent solution is
5.5 +378
= 383.5 grams.
to make the solution of 5.5 percent of KCl weighing 22 grams.
We have that for the Question "" it can be said that the mass of water should be added to 22.0 g of KCl to make a 5.50 % by mass solution is
W=378.5gram
From the question we are told
What mass of water should be added to 22.0 g of KCl to make a 5.50 % by mass solution?
Generally the equation for the water needed is mathematically given as
[tex]5.5=\frac{22}{22+w}*100\\\\Therefore\\\\5.5w=2200-121\\\\w=378g\\\\[/tex]
Therefore
The mass of water should be added to 22.0 g of KCl to make a 5.50 % by mass solution is
W=5.5 +378
W=378.5grams
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