Answer:
A=3(π/2)-1 au
Step-by-step explanation:
we have according to the graph that
f(x)=3
g(x)=cos(x)
Knowing A=∫|f(x)-g(x)|dx, then
[tex]A=\int\limits^a_b (f(x)-g(x)}) \, dx\\[/tex]; where a=0 and b=π/2
[tex]A=\int\limits^a_b (3-cos(x)){} \, dx[/tex]
A=(3x-sin(x)) evaluated 0 ≤ x ≤ π/2
A=(3(π/2)-sin(π/2))-(3.0-sin(0))
[tex]A=3\frac{\pi }{2}-1[/tex]
