Respuesta :
Answer: The molarity of NaOH solution is 0.273 M.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of KHP = 1.794 g
Molar mass of KHP = 204.2 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of KHP}=\frac{1.794g}{204.2g/mol}=0.0088mol[/tex]
The chemical reaction for the reaction of KHP and NaOH follows
[tex]KHC_8H_4O_4(aq.)+NaOH\rightarrow KNaC_8H_4O_4(aq.)+H_2O(l)[/tex]
By Stoichiometry of the reaction:
1 mole of KHP reacts with 1 mole of NaOH.
So, 0.0088 moles of KHP will react with = [tex]\frac{1}{1}\times 0.0088=0.0088mol[/tex] of NaOH
To calculate the molarity of NaOH, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]
We are given:
Moles of NaOH = 0.0088 moles
Volume of solution = [32.47 - 0.23] mL = 32.24 mL = 0.03224 L (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:
[tex]\text{Molarity of NaOH }=\frac{0.0088mol}{0.03224L}=0.273M[/tex]
Hence, the molarity of NaOH solution is 0.273 M.
