Given:
Side length of base = 8
Slant height = 6
To find:
The surface area of the square pyramid.
Solution:
Surface area:
[tex]$SA=A+\frac{1}{2} p s[/tex]
where A is the area of base
p is the perimeter of base
s is the slant height
Area of base (A) = 8 × 8
= 64
Perimeter of base(P) = 4 × 8
= 32
Substitute these in the formula:
[tex]$SA=64+\frac{1}{2} \times 32 \times 6[/tex]
[tex]$SA=64+96[/tex]
[tex]$SA=160[/tex]
The surface area of the square pyramid is 160 unit².
