Respuesta :
Answer:
The carrots can weight atmost 34.59 ounces so that it does not need to be repackaged.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 34 ounces
Standard Deviation, σ = 0.35 ounces
We are given that the distribution of weights of bags is a bell shaped distribution that is a normal distribution.
Formula:
[tex]z_{score} = \displaystyle\frac{x-\mu}{\sigma}[/tex]
We have to find the value of x such that the probability is 0.045
[tex]P( X > x) = P( z > \displaystyle\frac{x - 34}{0.35})=0.045[/tex]
[tex]= 1 -P( z < \displaystyle\frac{x - 34}{0.35})=0.045[/tex]
[tex]=P( z < \displaystyle\frac{x - 34}{0.35})=0.955[/tex]
Calculation the value from standard normal z table, we have,
[tex]\displaystyle\frac{x - 34}{0.35} = 1.695\\\\x = 34.59325\approx 34.59[/tex]
Thus, the carrots can weight atmost 34.59 ounces so that it does not need to be repackaged.
