Answer:
The acceleration of the crate is [tex]1.82\ m/s^2[/tex].
Explanation:
Given that,
Force, F = 750 N
Mass of the crate, m = 250 kg
The coefficient of friction is 0.12.
We need to find the acceleration of the crate. The net force acting on the crate is given by :
[tex]F=ma\\\\F-f=ma[/tex]
f is frictional force, [tex]f=\mu N=\mu mg[/tex]
[tex]F-\mu mg=ma\\\\a=\dfrac{F-\mu mg}{m}\\\\a=\dfrac{750-0.12\times 250\times 9.8}{250}\\\\a=1.82\ m/s^2[/tex]
So, the acceleration of the crate is [tex]1.82\ m/s^2[/tex]. Hence, this is the required solution.
