Answer: 17.8 pounds.
Explanation:
The radius of the Earth is 4000 mi.
now, a person right in the surface of the earth is located at a distance 4000 miles of the center, and we have that the weight will be something like:
W = 160 pounds = A/(4000)^2 pounds
where A is a constant that we do not know, but we can find the value:
A = 160*(4000)^2
Now, at a distance of 8000 miles to the surface we have:
W = A/(4000 + 8000)^2 = 160*(4000)^2/(12000)^2 = 17.8 pounds.
Answer:
Weight = 17.8 pounds
Explanation:
Given that the weight W of a person is inversely proportional to the distance of that person from the center of the earth, then W ∝1/d²
and W2/W1 = d1²/d2²
So W2 = W1× d1²/d2²
Given W1 = 160lb, d1 = 4000miles, d2 = (8000 + 4000) = 12000miles. This is because this distance is always measured from the center of the earth. At the earth's surface the distance from the earth's center is 4000miles so at a distance of 8000miles from the earth's surface the distance from the center would now be the addition of both distances.
So W2 = 160× 4000²/12000² = 17.8lb.
This law in operation is known as the inverse square law.
The weight is actually the force of gravity between the earth and the individual. It is an attractive force that decreases with increasing distance.
W = GMem/d²
Where G = gravitational constant = 6.67×10-¹¹ Nm²/kg²
Me = mass of the earth
m = mass of individual
d = distance from the center of the earth.
