Type A is 8 feet tall and grows at a rate of 18 inches per year. Type B is 9 feet tall and grows at a rate of 17 inches per year. Algebraically determine exactly how many years it will take for these trees to be the same height.

Respuesta :

Answer:

12 years.

Step-by-step explanation:

Le x represent number of years.

We have been given that type A is 8 feet tall and grows at a rate of 18 inches per year. So growth of type A in x years would be [tex]18x[/tex] inches.

1 feet = 12 inches.

8 feet = 8*12 inches = 96 inches.

9 feet = 9*12 inches = 108 inches.

The total height of type A would be [tex]96+18x[/tex] inches.

We are also told that type B is 9 feet tall and grows at a rate of 17 inches per year. So growth of type B in x years would be [tex]17x[/tex] inches and total height of type B would be [tex]108+17x[/tex] inches.

To find the years when both trees will be of the same height, we will equate height of both trees and solve for x as:

[tex]96+18x=108+17x[/tex]

[tex]96+18x-17x=108+17x-17x[/tex]

[tex]96+x=108[/tex]

[tex]96-96+x=108-96[/tex]

[tex]x=12[/tex]

Therefore, after 12 years the height of these trees will be the same.