Answer: 0.013 seconds
Explanation:
Given that
Mass of golf ball = 0.058 kg
Force = 272 N
Velocity = 62.0 m/s
Time taken = ?
Recall that force is the rate of change of momentum per unit time
i.e Force = Change in momentum / Time
i.e Force = (Mass x velocity) / Time
272N = (0.058 kg x 62.0 m/s) / Time
272N = 3.6kgm/s / Time
Time = (3.6kgm/s / 272N)
Time = 0.013 seconds
Thus, the ball was in contact with the club for 0.013 seconds
