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You leave on a trip in order to attend a meeting that will start after you begin your trip. Along the way you plan to stop for dinner. If the fastest you can safely drive is 65 mi/h, what is the longest time you can spend over dinner and still arrive just in time for the meeting

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lublana

Answer:

2.96 h

Explanation:

We are given that

Speed of man,v=65mi/h

Time ,t=9.9 h

Total distance,s=451 miles

We have to find the time which you can spend over dinner and still arrive juts in time for the meeting.

Distance,[tex]d=v\times t[/tex]

Using the formula

[tex]d=65\times 9.9=643.5 miles [/tex]

Difference between distance=643.5-451=192.5 miles

Time,=[tex]t'=\frac{difference\;in\;distance}{speed}[/tex]

[tex]t'=\frac{192.5}{65}=2.96 h[/tex]

Hence, you can spend maximum time over dinner=2.96 h

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