Answer:
[tex]\eta=0.067[/tex]
Explanation:
Given that
Temperature of warm water ,T₁ = 25 °C
Temperature of cold water ,T₂ = 5 °C
The maximum possible efficiency of any heat is will be same as the efficiency of the Carnot heat engine.Therefore the maximum efficiency of OTEC system is given as follows
[tex]\eta=1-\dfrac{T_2}{T_1}[/tex]
T should be Kelvin scale
Now by putting the values
[tex]\eta =1-\dfrac{5+273}{25+273}[/tex]
[tex]\eta=0.067[/tex]
Therefore the maximum efficiency will be 0.067 or 6.7%.
