Answer: The required confidence interval is (220.873,243.127).
Step-by-step explanation:
Since we have given that
Sample = n = 322
Mean = $232
Standard deviation= $36
At 94% confidence interval,
z = 1.88
So, the confidence interval for average would be
[tex]\bar{x}\pm z\dfrac{\sigma}{\sqrt{n}}\\\\=232\pm 1.88\times \dfrac{36}{\sqrt{37}}\\\\=232\pm 11.127\\\\=(232-11.127,232+11.127)\\\\=(220.873,243.127)[/tex]
Hence, the required confidence interval is (220.873,243.127).