The following data represent the flight time (in minutes) of a random sample of seven flights from one city to another city. 281, 269, 259, 265, 256, 259, 266 Compute the range and sample standard deviation of flight time. The range of flight time is 25 minutes. The sample standard deviation of flight time is nothing minutes.

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dfbustos dfbustos · Answer 1 · 2020-04-01T03:46:51+02:00

Answer:

[tex] Range = 281-256= 25[/tex]

In order to calculate the sample deviation we need to calculate the mean given by:

[tex] \bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]

And replacing we got:

[tex]\bar X= 265[/tex]

And the standard deviation can be calculated with this formula:

[tex] s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]

And replacing we got:

[tex]s = 8.426[/tex]

Step-by-step explanation:

For this case we have the following data given:

281, 269, 259, 265, 256, 259, 266

The range is defined as:

[tex] Range = Max -Min[/tex]

And if we replace we got:

[tex] Range = 281-256= 25[/tex]

In order to calculate the sample deviation we need to calculate the mean given by:

[tex] \bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]

And replacing we got:

[tex]\bar X= 265[/tex]

And the standard deviation can be calculated with this formula"

[tex] s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]

And replacing we got:

[tex]s = 8.426[/tex]