Respuesta :
Answer:
[tex]\hat p \sim N(p ,\sqrt{\frac{p(1-p)}{n}})[/tex]
With the following parameters
The mean is given by:
[tex] \mu_{\hat p} = 0.9[/tex]
And the standard error is given by:
[tex]\sigma_{\hat p}=\sqrt{\frac{0.9*(1-0.9)}{1700}}= 0.00728[/tex]
Step-by-step explanation:
For this case we know that we have a sample size n = 1700
And the estimated proportion of young adult Internet users is 0.9
We can check the conditions in order to use the normal approximation:
1) np = 1700*0.9 = 1530>10
2) n(1-p) = 1700*(1-0.9)= 170>10
3) Randomization: The data comes from a random sample
For this case we assume that the three conditions are satisfied so then the normal approximation is useful and for this case is given by:
[tex]\hat p \sim N(p ,\sqrt{\frac{p(1-p)}{n}})[/tex]
With the following parameters
The mean is given by:
[tex] \mu_{\hat p} = 0.9[/tex]
And the standard error is given by:
[tex]\sigma_{\hat p}=\sqrt{\frac{0.9*(1-0.9)}{1700}}= 0.00728[/tex]
