Answer : The number of moles of oxygen gas required are, 4.49 moles.
Explanation :
The balanced chemical reaction is:
[tex]2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(l)[/tex]
First we have to calculate the moles of butane gas.
As we know that, 1 mole of substance occupies 22.4 L volume of gas.
As, 22.4 L volume of butane gas present in 1 mole of butane gas
So, 15.5 L volume of butane gas present in [tex]\frac{15.5}{22.4}=0.692[/tex] mole of butane gas
Now we have to calculate the moles of oxygen gas.
From the balanced chemical reaction we conclude that,
As, 2 moles of butane gas react with 13 moles of oxygen gas
So, 0.692 moles of butane gas react with [tex]\frac{13}{2}\times 0.692=4.49[/tex] moles of oxygen gas
Therefore, the number of moles of oxygen gas required are, 4.49 moles.
