Answer:
[tex]K=0.0131M[/tex]
Explanation:
Hello,
In this case, the undergoing chemical reaction turns out:
[tex]CCl_4(g) \rightleftharpoons C(s)+ 2Cl_2(g)[/tex]
In such a way, by means of the mass of law action for such reaction, which is given below:
[tex]Kp=\frac{p_{Cl_2}^2}{p_{CCl_4}}[/tex]
And in terms of the change [tex]x[/tex] due to reaction extent:
[tex]p_{CCl_4}=p_{CCl_4}^0-x\\p_{Cl_2}=2x\\p_T=p_{CCl_4}+p_{Cl_2}=1.00-x+2x\\p_T=1.00+x[/tex]
[tex]x[/tex] results:
[tex]x=1.35 atm -1.00atm=0.35atm[/tex]
In such a way, Kp:
[tex]Kp=\frac{(2x)^2}{1.00-x} =\frac{(2*0.35atm)^2}{1.00atm-0.35atm}=0.754atm[/tex]
Nonetheless, K is asked instead of Kp, thus:
[tex]K=\frac{Kp}{(RT)^{\Delta \nu _{gas}}}[/tex]
Whereas:
[tex]\Delta \nu _{gas}=2-1=1[/tex]
Which is the change in the moles of gaseous species chlorine and carbon tetrachloride. Hence, we finally obtain:
[tex]K=\frac{0.754atm}{(0.082\frac{atm*L}{mol*K}*700K)^{1}}\\\\K=0.0131mol/L=0.0131M[/tex]
Best regards.
