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Two bird watchers position themselves at point A (the beach) and point C (the shed) which are 111 feet apart. The both spot a rare bird at point B using their binoculars. If they see the bird at 94º and 46º respectively, how far is the bird from the bird watcher in the shed (point C) (to the nearest foot). *

Respuesta :

Answer:120 ft

Step-by-step explanation:

Given

Beach(A) and Shed (C) is [tex]111[/tex] feet apart

If Two bird watchers set then at A and C and observe a bird at [tex]94^{\circ}[/tex] and  [tex]46^{\circ}[/tex]

Using Trigonometric relation

[tex]\tan 86=\frac{h}{x}---1[/tex]

[tex]\tan 46=\frac{h}{111+x}---2[/tex]

from 1 and 2

[tex]x\tan 86=(111+x)\tan 46[/tex]

[tex]x=8.66\ ft\approx 9\ ft[/tex]

Therefore bird is [tex]120\ ft[/tex] from point C

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