Answer:
The required radius is 2.62 cm
Explanation:
Given;
magnitude of current in wire, I = 1.31 A
magnetic field strength, B = 10 µT
Applying Biot Savart equation;
[tex]B = \frac{\mu_o I}{2\pi r} \\\\r = \frac{\mu_o I}{2\pi B}[/tex]
where;
r is the radius of the wire
μ₀ is constant = 4π x 10⁻⁷ Tm/A
I is the current in the wire
B is the magnetic field strength
Substitute the given values and calculate the radius
[tex]r = \frac{4 \pi *10^{-7} *1.31}{2\pi *10 *10^{-6}} = 2.62 *10^{-2} \ m = 2.62 \ cm[/tex]
Therefore, the required radius is 2.62 cm
