Answer:
The speed of electron is 891.8 [tex]\frac{m}{s}[/tex]
Explanation:
Given :
Wavelength [tex]\lambda = 130 \times 10^{-9}[/tex] m
According to the uncertainty principle,
[tex]\Delta x \Delta P = \frac{h}{2\pi }[/tex]
Where [tex]\Delta x =[/tex] difference in length means wavelength, [tex]\Delta P =[/tex] difference in momentum,
We know that [tex]\Delta P = m\Delta v[/tex]
Put value in main equation,
[tex]\Delta v = \frac{h}{2\pi m \Delta x}[/tex]
[tex]\Delta v = \frac{6.626 \times 10^{-34} }{6.28 \times 9.1 \times 10^{-31} \times 130 \times 10^{-9} }[/tex] ( ∵ [tex]h = 6.626 \times 10^{-34}[/tex] )
[tex]\Delta v =891.8[/tex] [tex]\frac{m}{s}[/tex]
Therefore, the speed of electron is 891.8 [tex]\frac{m}{s}[/tex]