A beam of electrons strikes a double slit, with the slit separation of 130 nm. The first-order diffraction maximum is seen at an angle of 5 degrees away from the beam's direction. What was the speed of the electrons

Respuesta :

Answer:

The speed of electron is 891.8 [tex]\frac{m}{s}[/tex]

Explanation:

Given :

Wavelength [tex]\lambda = 130 \times 10^{-9}[/tex] m

According to the uncertainty principle,

    [tex]\Delta x \Delta P = \frac{h}{2\pi }[/tex]

Where [tex]\Delta x =[/tex] difference in length means wavelength, [tex]\Delta P =[/tex] difference in momentum,

We know that [tex]\Delta P = m\Delta v[/tex]

Put value in main equation,

 [tex]\Delta v = \frac{h}{2\pi m \Delta x}[/tex]

 [tex]\Delta v = \frac{6.626 \times 10^{-34} }{6.28 \times 9.1 \times 10^{-31} \times 130 \times 10^{-9} }[/tex]                   ( ∵ [tex]h = 6.626 \times 10^{-34}[/tex] )

 [tex]\Delta v =891.8[/tex] [tex]\frac{m}{s}[/tex]

Therefore, the speed of electron is 891.8 [tex]\frac{m}{s}[/tex]