Answer:
[tex]K(2000K)=0.722\\K(3000K)=23.5[/tex]
Explanation:
Hello,
In this case, in terms of the Gibbs free energy of the given reaction, the equilibrium constant is computed as shown below:
[tex]K=exp(-\frac{\Delta G }{RT} )[/tex]
In such a way, since the given Gibbs correspond to formation of X, they will equal the Gibbs free energy of those reactions. Thus, at each temperature we obtain:
[tex]K(2000K)=exp(-\frac{5410J/mol}{8.314J/(mol*K)*2000K} )\\K(2000K)=0.722\\\\K(3000K)=exp(-\frac{-52480J/mol}{8.314J/(mol*K)*3000K} )\\K(3000K)=23.5[/tex]
Best regards.