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A car with a mass of 3,272 kg is rolling on a level road at 33.0 m/s. It receives an impulse with a magnitude of 8,411 N-s and its speed is reduced as much as possible by an impulse of this size. What was the car's speed after the impulse was applied

Respuesta :

Answer:

The car's speed after the impulse was applied is 35.57 m/s.

Explanation:

Given that,

Mass of the car, m = 3272 kg

Initial speed of the car, u = 33 m/s

Impulse received by the car, J = 8,411 N-s

Let v is the car's speed after the impulse was applied. Impulse is equal to the change in momentum. So,

[tex]J=m(v-u)\\\\v=\dfrac{J}{m}+u\\\\v=\dfrac{8411}{3272}+33\\\\v=35.57\ m/s[/tex]

So, the car's speed after the impulse was applied is 35.57 m/s.

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