Write an equation that represents the situation

Answer:
y = x - 3
Step-by-step explanation:
Given line passes through the points [tex] (3,\:0)=(x_1,\:y_1) \:\&\:(6,\:3)=(x_2,\:y_2) [/tex]
Equation of line in two point form is given as:
[tex] \frac{y - y_1}{y_1 - y_2} = \frac{x - x_1}{x_1 - x_2} \\ \\ \therefore \: \frac{y - 0}{0 - 3} = \frac{x - 3}{3 - 6} \\ \\ \therefore \: \frac{y }{- 3} = \frac{x - 3}{ - 3} \\ \huge \red{ \boxed{\therefore \: y = x - 3}} \\ \implies \: y = mx + b[/tex]
Answer: y = 1x - 3
Step-by-step explanation:
1. The equation to find slope is shown by the following:
[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex] = slope (another term for slope is "m")
Choose two coordinates on the graph to solve this problem.
I chose (15,12) and (9,6), although any other set of points would have worked
At this point, you would plug the x and y coordinates in their respective places and solve:
[tex]\frac{12-6}{15-9\\}[/tex] = [tex]\frac{6}{6}\\[/tex] = 1
Now we know the slope/m = 1
This is the equation so far: y = 1x+b
2: Now, we have to solve for b, or the y-intercept
To solve for b, we need to plug in an "(x,y)" coordinate into this equation:
[tex](y-y_{1}) = m(x-x_{1})[/tex]
Choose any coordinate from the graph. In this instance, i chose "(3,0)," but any other point would work.
(y-0) = 1(x-3) --> y = 1x - 3
The equation that represents the line is y = 1x - 3