Answer:
The molecular formula of the compound :[tex]C_4H_6O_2[/tex]
Explanation:
The empirical formula of the compound =[tex]C_2H_3O[/tex]
The molecular formula of the compound =[tex]C_{2n}H_{3n}O_n[/tex]
The equation used to calculate the valency is :
[tex]n=\frac{\text{molecular mass}}{\text{empirical mass}}[/tex]
We are given:
Mass of molecular formula = 86 g/mol
Mass of empirical formula = 43 g/mol
Putting values in above equation, we get:
[tex]n=\frac{86g/mol}{43g/mol}=2[/tex]
The molecular formula of the compound :
[tex]C_{2\times 2}H_{3\times 2}O_2=C_4H_6O_2[/tex]
