Draw a Punnett square of an Ss x ss cross. The S allele codes for long stems in pea plants and the s allele codes for short stems. If S is dominant to s, what percentage of the offspring would you expect to have each phenotype?

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Answer:

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Ver imagen kacholianehal

The punnet square is used to predict phenotypes.

50% of the offsprings would have long stems, while the other 50% would have short stems.

See attachment for the SS vs ss cross

From the attachment, we have the following observations

[tex]n = 4[/tex] --- number of squares

[tex]Ss =2[/tex]

[tex]ss = 2[/tex]

Because S is dominant over s;we can write Ss as S.

So, we have:

[tex]n = 4[/tex]

[tex]S = 2[/tex]

[tex]s =2[/tex]

The percentage of each offspring calculated as follows is:

[tex]S\% = \frac{S}{n} \times 100\%[/tex]

[tex]S\% = \frac{2}{4} \times 100\%[/tex]

[tex]S\% = 0.5 \times 100\%[/tex]

[tex]S\% = 50\%[/tex]

[tex]s\% = \frac{s}{n} \times 100\%[/tex]

[tex]s\% = \frac{2}{4} \times 100\%[/tex]

[tex]s\% = 0.5 \times 100\%[/tex]

[tex]s\% = 50\%[/tex]

Hence, 50% of the offsprings would have long stems, while the other 50% would have short stems.

Read more about the punnet square at:

https://brainly.com/question/3154616

Ver imagen MrRoyal