Respuesta :

owiso

Answer:

=x²_7x+10

Step-by-step explanation

number 2

[x-2][x-5]

x[x_5]_2[x_5]=

[x²-5x-2x+10]=

=x²_7x+10

number3

x²+6x+5

    sum=6

    product=5

    factors=[1,5]

x+1=0

  x=_1

x+5=0

  x=_5

number 4

simultaneous equation

x+y=4

x+4y=7

[_3y=_3] divide both side by negative 3 to get Y as 1

equate 1 to x+y=4 to get X as 3

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