Step-by-step explanation:
[tex] - 3y + 10 = x...(1) \\ 10x + 7y = - 38...(2) \\ from \: equations \: (1) \: and \: (2) \\ 10( - 3y + 10) + 7y = - 38 \\ - 30y + 100 + 7y = - 38 \\ - 23y = - 38 - 100 \\ - 23y = - 138 \\ y = \frac{ - 138}{ - 23} \\ \huge \red { \boxed{y = 6}} \\ substituting \: y = 6 \: in \: equation \: (1) \\ x = - 3 \times 6 + 10 = - 18 + 10 = - 8 \\ \huge \red { \boxed{x = - 8}} \\ \\ \: \: \huge \purple{ \boxed{(x, \: \: y) = ( - 8, \: \: 6)}}[/tex]
