Answer:
[tex]5 \frac{1}{3} [/tex]
Step-by-step explanation:
Assuming We want to evaluate
[tex] \frac{3}{2y - 3} + \frac{5}{3} z[/tex]
When y=6 and z=3.
We substitute to get:
[tex] \frac{3}{2 \times 6 - 3} + \frac{5}{3} \times 3[/tex]
We multiply to get:
[tex]\frac{3}{12 - 3} + \frac{15}{3}[/tex]
We simplify the denominator to get:
[tex]\frac{3}{9} + \frac{15}{3}[/tex]
Reduce the first fraction:
[tex]\frac{1}{3} + \frac{15}{3}[/tex]
Add the numerator and keep one denominator for they are like fractions
[tex] \frac{16}{3} [/tex]
Write as a mixed number:
[tex]5 \frac{1}{3} [/tex]
