Answer:
The y-intercept is: (0, 15)
The graph is also attached below.
Step-by-step explanation:
Given
[tex]f\left(x\right)=-3\left(x-2\right)^2+27[/tex]
Determining the y-intercept
As we know that y-intercept is the point on a graph where x = 0
so
Putting x = 0 in the function
[tex]y=-3\left(0-2\right)^2+27[/tex]
[tex]y=-2^2\cdot \:3+27[/tex]
[tex]y=-12+27[/tex]
[tex]\mathrm{Add/Subtract\:the\:numbers:}\:-12+27=15[/tex]
[tex]y=15[/tex]
Therefore, the y-intercept is: (0, 15)
The graph is also attached below.
