The pressure acting on an area of 20 m² with force 50 N is 2.5 Nm² and the pressure acting on an area of 0.5 m² with force 50 N is 100 Nm².
The force acting on area of 3 m² with pressure 10 Pa is 30 N.
Explanation:
Pressure acting on any surface is the amount of force experienced by that surface in a given area. So it is the ratio of force to area of the object under consideration.
As here the force is said to be 50 N and the area is said to be 20 m², the pressure will be
[tex]Pressure = \frac{Force}{Area} = \frac{50}{20}=2.5 Nm^{2}[/tex]
So, pressure is inversely proportional to the area and directly proportional to the force acting on the surface. As it can be seen that on decreasing the area to 0.5 m², there will be increase in the pressure as shown below,
[tex]Pressure = \frac{50}{0.5} = 100 Nm^{2}[/tex]
Thus, the pressure increased to 100 Nm² from 2.5 Nm² on decreasing the area from 20 m² to 0.5 m².
Similarly, if 10 Pa pressure is acting on an area of 3 m², then the force acting on this region will be the product of pressure with the area.
[tex]Force = Pressure * Area = 10 * 3 = 30 N.[/tex]
Thus, the pressure acting on an area of 20 m² with force 50 N is 2.5 Nm² and the pressure acting on an area of 0.5 m² with force 50 N is 100 Nm².
The force acting on area of 3 m² with pressure 10 Pa is 30 N.
