Answer:
50°
Step-by-step explanation:
[tex]m(arc ADQ)=2 \times \angle AUQ \\ \hspace{64 pt}= 2\times \: 111 \degree \\ \hspace{64 pt}= 222 \degree \\ m(arc ADQ) + m(arc QU) \\+m(arc AU) = 360° \\ \therefore \: 222 \degree + 88 \degree +m(arc AU) = 360° \\ \therefore \: 310 \degree +m(arc AU) = 360° \\ \therefore \: m(arc AU) = 360° - 310 \degree \\ \huge \red{ \boxed{\therefore \: m(arc AU) = 50°}} \\ [/tex]
