Answer:
The observer sees the space-probe 9.055m long.
Explanation:
Let [tex]L_0[/tex] be the length of the space-probe when measured at rest, and [tex]L[/tex] be its length as observed by an observer moving at velocity [tex]v[/tex], then
[tex](1).\: \: L = L_0\sqrt{1-\dfrac{v^2}{c^2} }[/tex]
Now, we know that [tex]L_0 = 29.0m[/tex] and [tex]v = 0.95c[/tex], and putting these into [tex](1)[/tex] we get:
[tex]L = 29\sqrt{1-\dfrac{(0.95c)^2}{c^2} }[/tex]
[tex]L = 29\sqrt{1-0.95^2 }[/tex]
[tex]\boxed{L = 9.055m}[/tex]
Thus, an observer moving at 0.95c observes the space-probe to be 9.055m long.
