contestada

In a DNA molecule, if 38% of the molecular bases are C (cytosine), what percent of the bases are T (thymine)?

Respuesta :

In a DNA molecule containing 38% of Cytosine(C), The percentage of Thymine(T) is 12%

According to Chargaff's Rule:

  • A+G=C+T
  • Adenine(A) always pairs with Thymene(T), which means A=T
  • Guanine(A) always pairs with Cytosine(C), which means G=C

Since the proportion of C is 38%, the Guanine will also be 38%

A+T= 100-76

A+T= 24

A=12 and T= 12

Therefore, we can conclude that The percentage of Thymine(T) is 12%

For more about Chargaff'https://brainly.com/question/15063347?referrer=searchResultss rule you can refer to the link:

All the information for the genes is stored in the DNA. DNA stands for deoxyribose nucleic acid. The DNA is present at the chromosome as in highly coiled form in the nucleus.

The DNA is made from the following:-

  • Deoxyribose sugar
  • Phosphate group
  • Nitrogenous base

The thymine requires to join with the adenine is 12% because.

DNA has 4 nitrogenous bases, that are adenine, guanine, cytosine, and thymine. The adenine binds to the thymine with the double hydrogen bond in the same ratio and the guanine binds to the cytosine with the triple hydrogen bond.

Hence, according to the Erwin Chargaff rule, the ratio of purine to pyrimidines will be the same. hence the percentage of the "T" will be 12%.

For more information, refer to the link;-

https://brainly.com/question/264225