Answer:
The answer to your question is V2 = 31.97 L
Explanation:
Data
Volume 1 = 30 L
Pressure 1 = 100 kPa
Temperature 1 = 15°C
Volume 2 = ?
Pressure 2 = 115 kPa
Temperature 2 = 80°C
Process
1.- Convert temperature to °K
Temperature 1 = 15 + 273 = 288°K
Temperature 2 = 80 + 273 = 353°K
2.- Use the Combined gas law to solve this problem
P1V1/T1 = P2V2/T2
-Solve for V2
V2 = P1V1T2 / T1P2
-Substitution
V2 = (100 x 30 x 353) / (288 x 115)
- Simplification
V2 = 1059000 / 33120
- Result
V2 = 31.97 L
Answer:
The new volume is 31.97 L
Explanation:
Step 1: Data given
The initial volume = 30.0 L
The initial pressure = 100 kPa
Temperature = 15.0 °C = 288 K
The temperature is increased to 80.0 °C = 353 K
The pressure increases to 115 kPa
Step 2: Calculate the new volume
P1*V1 /T1 = P2*V2/T2
⇒with P1 = the initial pressure = 100 kPa
⇒with V1 = the initial volume = 30.0 L
⇒with T1 = the initial temperature = 288 K
⇒with P2 = the increased pressure = 115 kPa
⇒with V2 = the new volume = TO BE DETERMINED
⇒with T2 = the increased temperature = 353 K
(100 * 30.0)/288 = (115 * V2)/353
10.417 = (115 * V2)/353
V2 = 31.97 L
The new volume is 31.97 L
