gentrgg
contestada

consider the graph of the following qudratic equation. y= -x^2 -10x + 24.What is the y-value of the vertex?

Respuesta :

Given that the quadratic equation is [tex]y=-x^{2}-10 x+24[/tex]

We need to determine the y - value of the vertex.

The x - value of the vertex:

The x - value of the vertex can be determined using the formula,

[tex]x=-\frac{b}{2 a}[/tex]

where [tex]a=-1, b=-10, c=24[/tex]

Substituting these values, we get;

[tex]x=-\frac{(-10)}{2(-1)}[/tex]

Simplifying the terms, we get;

[tex]x=-\frac{-10}{-2}[/tex]

[tex]x=-5[/tex]

Thus, the x - value of the vertex is -5.

The y - value of the vertex:

The y - value of the vertex can be determined by substituting the x - value of the vertex ( x = -5) in the equation [tex]y=-x^{2}-10 x+24[/tex]

Thus, we get;

[tex]y=-(-5)^{2}-10(-5)+24[/tex]

Simplifying the values, we have;

[tex]y=-25+50+24[/tex]

[tex]y=49[/tex]

Thus, the y - value of the vertex is 49.