Respuesta :
1.6 X [tex]10^{-4}[/tex] M is the [H] in a HC102 solution that has a pH of 3.78.
Explanation:
Given:
pH of the acid = 3.78
[H+] ion concentration = ?
The dissociation of the acid is shown as:
[tex]H^{+}[/tex] + [tex]ClO^{2-}[/tex] ⇔ HClO2
however, weak acid like HClO2 does not dissociate or ionize completely which causes low hydrogen ion release in the solution.
pH is calculated by applying the formula:
pH = - log [H+]
To calculate the H+ ion concentration the equation will be expressed as:
[H+] = [tex]10^{-pH}[/tex]
= [tex]10^{-3.78}[/tex]
= 1.6 X [tex]10^{-4}[/tex] M
The concentration or molarity of the Hydrogen ion in the solution of the acid is 1.6 X [tex]10^{-4}[/tex] M.
The {H} in an HC102 solution that has a pH of 3.78 is 1.6*10^-4.
Calculation of the value of H:
Since
pH of the acid = 3.78
[H+] ion concentration = ?
Now the acid dissociation should be
H+ + ClO^2 = HCIO2
Here weak acid such as HClO2 does not dissociate or ionize completely which leads to low hydrogen ion release in the solution.
ph = -log{H+}
So,
{H+} = 10^-pH
= 10^-3.78
= 1.6*10^-4M
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