Answer:
15
Step-by-step explanation:
We find the union of the sets, one for each day.
Monday = {M, O, N, D, A, Y}
Tuesday = {T, U, E, S, D, A, Y}
Wednesday = {W, E, D, N, E, S, D, A, Y} = {W, E, D, N, S, A, Y}
Thursday = {T, H, U, R, S, D, A, Y}
Friday = {F, R, I, D, A, Y}
Saturday = {S, A, T, U, R, D, A, Y} = {S, A, T, U, R, D, Y}
Sunday = {S, U, N, D, A, Y}
Duplicates have been removed in each set.
The union is
Week = Monday ∪ Tuesday ∪ Wednesday ∪ Thursday ∪ Friday ∪ Saturday ∪ Sunday
Week = {M, O, N, D, A, Y} ∪ {T, U, E, S, D, A, Y} ∪ {W, E, D, N, S, A, Y} ∪ {T, H, U, R, S, D, A, Y} ∪ {F, R, I, D, A, Y} ∪ {S, A, T, U, R, D, Y} ∪ {S, U, N, D, A, Y}
Week = {M, O, N, D, A, Y, T, U, E, S, W, H, R, F, I}
(Duplicates are also removed)
The number of elements in Week is n(Week) = 15