the line-of-sight distance from the television camera to the base of the stadium is 1449.28 m .
Step-by-step explanation:
A blimp provides aerial television views of a baseball game. The television camera sights the stadium at a 12° angle of depression. The altitude of the blimp is 300 m. We need to find What is the line-of-sight distance from the television camera to the base of the stadium . Let's find out:
According to question , given scenario is in a right angle triangle where
[tex]Perpendicular=300\\Hypotenuse=?\\x=12[/tex] , where x is angle of depression.
We know that [tex]sinx= \frac{Perpendicular}{Hypotenuse}[/tex]
⇒ [tex]sin12= \frac{300}{Hypotenuse}[/tex]
⇒ [tex]Hypotenuse= \frac{300}{Sin12}[/tex]
⇒ [tex]Hypotenuse= \frac{300}{0.207}[/tex]
⇒ [tex]Hypotenuse= 1449.28m[/tex]
Therefore , the line-of-sight distance from the television camera to the base of the stadium is 1449.28 m .
