Answer:
Electric field strength is 0.75 N/C
Explanation:
As we know that electric field is defined as the force experience by a unit charge
Here we know that force experience by given charge
[tex]Q = 6.0 \times 10^{-4}C[/tex]
is given as
[tex]F = 4.5 \times 10^[-4} N[/tex]
so we have
[tex]E = \frac{F}{Q}[/tex]
[tex]E = \frac{4.5 \times 10^{-4}}{6.0 \times 10^{-4}}[/tex]
[tex]E = 0.75 N/C[/tex]
