angelperce
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Which equation is an equation of a circle with a radius of 3 and it’s center is at (5,-2)?

(X-5)2+(y+2)2=3

(X+5)2+(y-2)2=9

(X+5)2+(y-2)2=3

(X-5)2+(y+2)2=9

Respuesta :

[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{5}{ h},\stackrel{-2}{ k})\qquad \qquad radius=\stackrel{3}{ r}\\[1em] [x-5]^2+[y-(-2)]^2=3^2\implies (x-5)^2+(y+2)^2=9[/tex]

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