Step-by-step explanation:
[tex]2 {x}^{2} + 3x - 4 = 0 \\ 16 {x}^{2} + 24x - 32 = 0 \\ 16 {x}^{2} + 24x + 9 = 41 \\ {(4x)}^{2} + 2 \times 4x \times 3 + {(3)}^{2} = 41 \\ {(4x + 3)}^{2} = 41 \\ |4x + 3| = \sqrt{41} \\ 4x + 3 = + - \sqrt{41} \\ 4x = - 3 + - \sqrt{41} \\ x = \frac{ - 3 + - \sqrt{41} }{4} [/tex]
