Answer:
(x+2)1x-8)=0
x=-2 or x=8
Step-by-step explanation:
The given quadratic expression is
[tex]2 {x}^{2} - 12x - 32[/tex]
We equate this expression to zero to get:
[tex]2 {x}^{2} - 12x - 32 = 0[/tex]
Let us divide through by 2 to get:
[tex] {x}^{2} - 6x - 16 = 0[/tex]
Split the middle term to get:
[tex]{x}^{2} - 8x + 2x - 16 = 0[/tex]
Factor
[tex]{x}(x - 8) + 2(x - 8) = 0[/tex]
Factor further to get
[tex](x - 8)(x + 2) = 0[/tex]
The solution are
[tex]x = - 2 \: and \: x = 8[/tex]
