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A solenoid of length 0.250 m and radius 0.0250 m is comprised of 440 turns of wire. Determine the magnitude of the magnetic field at the center of the solenoid when it carries a current of 12.0 A.

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fahadisahadam

Answer: 0.02654

Explanation:

in the attachment

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Answer:0.00265T

Explanation: magnetic field at the center of the solenoid(B)= magnetic permeability*number of turns(n)*current. But n=N/L=440/0.250=1760

Magnetic permeability =4*3.142*10^-7=0.0000001257T.m/A

B = 0.0000001257*10^-7*1760*12.0=0.00265T

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